1. We the Travellers — I
Solutions to all Let Us Do, Let Us Think and Pastime Mathematics questions. CBSE / NCERT Class 5 Maths Mela.
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Reading and Writing Large Numbers
1,000, 2,000, 3,000, 4,000, 5,000, 6,000, 7,000, 8,000, 9,000.
When we add a thousand to 9,000, we get 10,000 (ten thousand).
| Number | TTh | Th | H | T | O | Number Name |
|---|---|---|---|---|---|---|
| 10,033 | 1 | 0 | 0 | 3 | 3 | Ten thousand thirty-three |
| 10,458 | 1 | 0 | 4 | 5 | 8 | Ten thousand four hundred fifty-eight |
| 11,214 | 1 | 1 | 2 | 1 | 4 | Eleven thousand two hundred fourteen |
| 13,520 | 1 | 3 | 5 | 2 | 0 | Thirteen thousand five hundred twenty |
| 20,000 | 2 | 0 | 0 | 0 | 0 | Twenty thousand |
| 45,867 | 4 | 5 | 8 | 6 | 7 | Forty-five thousand eight hundred sixty-seven |
Let Us Do
(a) 456 → 567 → 678 → 789 → 900 → 1,011 → 1,122
Pattern: add 111 each time.
(b) 1,050 → 2,100 → 3,150 → 4,200 → 5,250 → 6,300 → 7,350
Pattern: add 1,050 each time.
(c) 5,501 → 6,401 → 7,301 → 8,201 → 9,101 → 10,001 → 10,901
Pattern: add 900 each time.
(d) 10,100 → 10,200 → 10,300 → 10,400 → 10,500 → 10,600 → 10,700 → 10,800 → 10,900 → 11,000
Pattern: add 100 each time.
(e) 10,105 → 10,125 → 10,145 → 10,165 → 10,185 → 10,205 → 10,225 → 10,245 → 10,265 → 10,285
Pattern: add 20 each time.
(f) 10,992 → 10,993 → 10,994 → 10,995 → 10,996 → 10,997 → 10,998 → 10,999 → 11,000 → 11,001
Pattern: add 1 each time.
(g) 10,794 → 10,796 → 10,798 → 10,800 → 10,802 → 10,804 → 10,806 → 10,808 → 10,810 → 10,812
Pattern: add 2 each time.
(h) 73,005 → 72,004 → 71,003 → 70,002 → 69,001 → 68,000 → 66,999 → 65,998 → 64,997 → 63,996
Pattern: subtract 1,001 each time.
(i) 82,350 → 83,350 → 84,350 → 85,350 → 86,350 → 87,350 → 88,350 → 89,350 → 90,350 → 91,350
Pattern: add 1,000 each time.
| Number | Number Name |
|---|---|
| 8,045 | Eight thousand forty-five |
| 7,209 | Seven thousand two hundred nine |
| 10,599 | Ten thousand five hundred ninety-nine |
| 10,743 | Ten thousand seven hundred forty-three |
| 20,869 | Twenty thousand eight hundred sixty-nine |
| 13,579 | Thirteen thousand five hundred seventy-nine |
| 10,010 | Ten thousand ten |
| 56,491 | Fifty-six thousand four hundred ninety-one |
| 45,045 | Forty-five thousand forty-five |
| 39,593 | Thirty-nine thousand five hundred ninety-three |
| 50,005 | Fifty thousand five |
| 26,050 | Twenty-six thousand fifty |
| 81,200 | Eighty-one thousand two hundred |
| 90,009 | Ninety thousand nine |
| 23,230 | Twenty-three thousand two hundred thirty |
| 36,001 | Thirty-six thousand one |
18,926 < 34,407 < 34,740 < 40,347 < 40,473 < 47,340 < 73,404 < 74,430
No, the student is not correct.
9,990 is a 4-digit number. 49,014 is a 5-digit number.
49,014 has 4 ten thousands, but 9,990 has no ten thousand.
So, 49,014 > 9,990.
On the number line, 9,990 lies just before 10,000. 49,014 lies just before 50,000.
(a) Interchange any two digits in 1,478 to make a number larger than 5,500.
Interchange 1 and 7: 7,418. Or interchange 1 and 8: 8,471.
(b) Interchange two digits of 10,593 to make a number —
i) Between 11,000 and 15,000: interchange 0 and 3 → 13,590
ii) More than 35,000: interchange 1 and 5 → 50,193 (or 1 and 9 → 90,513)
(c) Interchange two digits of 48,247 to make a number —
i) As small as possible: interchange 4 and 2 → 28,447
ii) As big as possible: interchange 4 and 8 → 84,247
Nearest Tens, Hundreds and Thousands
2,300 is the nearest hundred of 2,346. It will need 46 jumps to reach 2,300.
2,000 is the nearest thousand of 2,346. It will need 346 jumps to reach 2,000.
| Number | Nearest Tens | Nearest Hundreds | Nearest Thousands |
|---|---|---|---|
| 3,176 | 3,180 | 3,200 | 3,000 |
| 4,017 | 4,020 | 4,000 | 4,000 |
| 5,789 | 5,790 | 5,800 | 6,000 |
| 8,203 | 8,200 | 8,200 | 8,000 |
Let Us Think
Circle 7,030 and 6,999.
7,030 → nearest hundred 7,000 and nearest thousand 7,000.
6,999 → nearest hundred 7,000 and nearest thousand 7,000.
7,126 (7,100 and 7,000) and 7,835 (7,800 and 8,000) give different results.
(a) 38 and 42 — both have nearest ten 40.
(b) 360 and 430 — both have nearest hundred 400.
(c) 3,700 and 4,200 — both have nearest thousand 4,000.
Many other answers are possible.
(a) 1,198 → nearest ten 1,200 and nearest hundred 1,200.
(b) 4,970 → nearest hundred 5,000 and nearest thousand 5,000.
(c) 6,998 → nearest ten, hundred and thousand are all 7,000.
Many other answers are possible.
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Travelling, Now and Then — Let Us Do
Distance in 1 hour = 15 km
Distance in 4 hours = 15 × 4 = 60 km
She will cover 60 km in 4 hours.
Total students = 461 + 439 = 900
| Mode of travel | People in one vehicle | Vehicles needed |
|---|---|---|
| (a) Bicycle | 2 | 900 ÷ 2 = 450 |
| (b) Autorickshaw | 3 | 900 ÷ 3 = 300 |
| (c) Car | 4 | 900 ÷ 4 = 225 |
| (d) Big car | 6 | 900 ÷ 6 = 150 |
| (e) Tempo traveller | 10 | 900 ÷ 10 = 90 |
| (f) Boat | 20 | 900 ÷ 20 = 45 |
| (g) Minibus | 25 | 900 ÷ 25 = 36 |
| (h) Aeroplane | 180 | 900 ÷ 180 = 5 |
Finding Large Numbers Around Us
The total number of words in one chapter of the textbook is a 4-digit number.
For example, a chapter of 16 pages with about 150 words on each page has about 2,400 words.
Answers depend on your school. Count and write. Example: (a) Our school has 18 classrooms. (b) There are 42 students in my class. (c) Our classroom has 336 books in total.
(i) 4-digit: the total number of pages in all the books in our bags.
(ii) 5-digit: the total number of words in all the textbooks of the class.
(i) A tree: the number of leaves on a big tree; the number of mangoes on a mango tree in a season.
(ii) A village or town: the number of people living there; the number of houses; the number of vehicles.
Pastime Mathematics
All three reach the other side safely in 7 trips.
In Trip 3, he can take the grass instead of the lion. The rest of the steps stay the same.
Let your friend play first.
After each of your turns, keep both piles equal.
If your friend takes some pebbles from one pile, take the same number from the other pile.
In the end, your friend empties one pile and you pick the last pebble. So you win.
(1) Observe the differences you get in each step. Do you notice anything in common?
The differences are 36, 27, 45 and 9. All of them are in the multiplication table of 9.
The sum of the digits of each difference is 9.
(2) Try the puzzle using any other pair of digits.
Take 2 and 5: 52 − 25 = 27, 72 − 27 = 45, 54 − 45 = 9.
All differences are multiples of 9. We get 9 in the end.
(3) What digits can you choose so that you get a 1-digit number in the first step itself?
Choose two digits that differ by 1 (consecutive digits).
Examples: 4 and 5 (54 − 45 = 9), 2 and 3 (32 − 23 = 9), 7 and 8 (87 − 78 = 9).
(4) Find different digits such that the difference between the numbers is 27.
Choose digits that differ by 3: 1 and 4 (41 − 14 = 27), 2 and 5, 3 and 6, 4 and 7, 5 and 8, 6 and 9.
(5) Extend Mira’s table so that the differences in digits are 2, 3, 5 and 7.
| Digits | Difference in digits | Difference in numbers |
|---|---|---|
| 1, 3 | 3 − 1 = 2 | 31 − 13 = 18 |
| 1, 4 | 4 − 1 = 3 | 41 − 14 = 27 |
| 1, 6 | 6 − 1 = 5 | 61 − 16 = 45 |
| 1, 8 | 8 − 1 = 7 | 81 − 18 = 63 |
What do the differences between the digits indicate? The difference in numbers is 9 times the difference in digits. For example, 9 × 4 = 36.
Numbers that give a 1-digit number in the third subtraction: digits that differ by 3 or 8. For example, 14, 25, 36, 47, 58, 69 and 19 (and their reverse numbers). For 41: 27 → 45 → 9.
Maximum number of subtractions: digits that differ by 2, such as 1 and 3, 2 and 4, 3 and 5, 4 and 6, 5 and 7, 6 and 8, 7 and 9. They take 5 subtractions: 18 → 63 → 27 → 45 → 9.
Let Us Do
23,600, 23,700, 23,800, 23,900 and 24,000
38,200, 38,300, 38,400, 38,500 and 38,550
67,543 > 56,987. So, Sheetal’s car has been driven more.
₹39,999, ₹49,900, ₹89,999, ₹90,000, ₹93,743, ₹94,983
Town 6 (66,540), Town 1 (65,232), Town 3 (56,380), Town 2 (53,231), Town 4 (51,336), Town 5 (45,858)
43,000, 44,000, 45,000, 46,000, 47,000, 48,000, 49,000, 50,000, 51,000, 52,000 and 53,000
(a) 783 = 700 + 80 + 3
(b) 8,062 = 8,000 + 60 + 2
(c) 9,980 = 9,000 + 900 + 80
(d) 10,304 = 10,000 + 300 + 4
(e) 23,004 = 20,000 + 3,000 + 4
(f) 70,405 = 70,000 + 400 + 5
(a) 983 = 90 Tens + 83 Ones
(b) 68 = 5 Tens + 18 Ones
(c) 607 = 4 Hundreds + 207 Ones
(d) 5,621 = 4 Thousand + 16 Hundreds + 2 Tens + 1 Ones
(e) 7,069 = 5 Thousand + 20 Hundreds + 69 Ones
(f) 37,608 = 2 Ten Thousand + 17 Thousand + 6 Hundreds + 8 Ones
(g) 43,001 = 3 Ten Thousand + 13 Thousand + 0 Hundreds + 1 Ones
(a) Notes of ₹10 in ₹7,934 = 793
(b) Notes of ₹100 in ₹7,934 = 79
(c) Thousands in 7,934 = 7
(d) ₹500 notes in ₹7,934 = 15 (7 thousands = 14 notes of ₹500, and 934 has one more ₹500.)
(e) Notes of ₹10 in ₹65,342 = 6,534
(f) Notes of ₹100 in ₹65,342 = 653
(g) Thousands in 65,342 = 65
(h) ₹500 notes in ₹65,342 = 130 (65 thousands = 130 notes of ₹500. 342 is less than 500.)
King’s Horses
No. There were only 19 horses.
The horse in the corner was counted twice. It was counted on two sides.
So, 5 × 4 = 20 is wrong. Horses in the corners belong to two sides.
Put 1 horse in two opposite corners. Put 2 horses in each of the other 8 side places (non-corner). Keep the other two corners empty.
Each side = 1 + 2 + 2 + 0 = 5. Total = 1 + 1 + (8 × 2) = 18.
Put more horses in the corners, because a corner horse is counted on two sides.
Keep 3 horses in two opposite corners and 2 horses in the other two corners. Keep all other places empty.
Each side = 3 + 2 = 5. Total = 3 + 3 + 2 + 2 = 10 horses.
So, from 18 horses, the thief can steal 8 more horses before the king notices.