Class 8 Mathematics · Part 2 · Chapter 5

5. Tales by Dots and Lines

Solutions to all Figure it Out and in-text questions. CBSE Class 8 Mathematics, NCERT Ganita Prakash Part 2.

Advertisement

5.1 The Balancing Act

1Can you explain how the mean is the centre of each collection? Is the mean the midpoint of the two extremes?

The mean is the balancing point. The total distance of the values below the mean equals the total distance of the values above it.

It is not always the midpoint of the smallest and largest values. For example, for 10, 10, 11, 17 the mean is 12: distances on the left are 2 + 2 + 1 = 5, and on the right 17 − 12 = 5. But the midpoint of 10 and 17 is 13.5.

2What happens to the mean when an existing value is removed? What if a value equal to the mean is included or removed?

Removing a value greater than the mean makes the mean decrease. Removing a value less than the mean makes it increase.

Including or removing a value equal to the mean does not change the mean. In the fair-share idea, that value already has exactly the fair share, so nothing needs to be shared.

3Can we include 2 values (or 3 values) and keep the mean unchanged? Include 2 values greater than the mean and 1 value less than the mean, keeping the mean the same.

Yes. The total distance above the mean must equal the total distance below it.

For a mean of 10: include 12 and 8 (2 above and 2 below). For three values: include 11, 12 (distances 1 + 2 = 3 above) and 7 (distance 3 below). The mean stays 10.

4Data: 8, 3, 10, 13, 4, 6, 7, 7, 8, 8, 5. Find its mean. If every value increases by 10, what is the new mean?

Sum = 79, number of values = 11. Mean = 79 ÷ 11 ≈ 7.18.

When every value increases by 10, the mean also increases by 10. New mean ≈ 17.18.

5Using algebra, what is the average when 2 is subtracted from every value?

New average = (x1 − 2) + (x2 − 2) + … + (xn − 2)n = x1 + … + xn − 2nn = a − 2.

So the average decreases by 2. In fair-share terms, if everyone gives back 2, each fair share is 2 less.

Spreadsheets

6Which cell has Farooq’s Maths marks? What data is in cell B7? In which subjects has Ashwin scored more than 30 marks?

Farooq’s Maths marks are in cell E5.

B7 has Gowri’s Odia marks, 27

Ashwin scored more than 30 in Telugu (31), English (33) and Maths (34)

7What formula finds the class average in Science? Is the Odia average greater than the Telugu average?

=AVERAGE(G2:G23)

Class averages: Odia ≈ 31.23, Telugu ≈ 33.59, English ≈ 32.64, Maths ≈ 34.14, Social Science ≈ 31.36, Science ≈ 33.14.

No, the Odia average is less than the Telugu average.

Total marks of a student, e.g. Ratna: =SUM(B2:G2) = 200.

Figure it Out (Page 113)

1Find the mean of (i) the first 50 natural numbers (ii) the first 50 odd numbers (iii) the first 50 multiples of 4.

(i) (1 + 50) ÷ 2 = 25.5

(ii) (1 + 99) ÷ 2 = 50

(iii) (4 + 200) ÷ 2 = 102

Observation: For numbers that go up by the same step, the mean is the average of the first and the last number.

2One dot is missing. Mark the missing value so that the mean is 9.

The plot shows 4, 7, 8, 8, 9, 9, 9, 9, 9, 11 (10 values, sum 83).

With 11 values and mean 9, the sum must be 99.

Missing value = 99 − 83 = 16

3The average height is 150.2 cm, but each student wore shoes adding 1 cm. (i) Must the heights be measured again? (ii) What is the correct average?

(i) No. Every value is 1 cm more, so the mean is also 1 cm more. Just subtract 1.

(ii) Correct average = (d) 149.2 cm

4Which album has a mean song length of 5.57 minutes?

Album A. All its dots lie between 5 and 6.5 minutes, so its mean is near 5.6. Album B’s dots are mostly between 0.5 and 5, and Album C’s between 3.5 and 4.5, so their means are much smaller.

5Find the median of 8, 10, 19, 23, 26, 34, 40, 41, 41, 48, 51, 55, 70, 84, 91, 92.

There are 16 values. Median = average of the 8th and 9th values = (41 + 41) ÷ 2 = 41

(i) Including any one value keeps the median 41, because the 8th and 9th values are both 41.

(ii) Include one value ≤ 41 and one value ≥ 41 (for example 30 and 60, or 41 and 41).

(iii) Removing any one value keeps the median 41 (the new middle value is still a 41).

6Always true, sometimes true or never true?

(i) Removing a value less than the median will decrease the median.

Never true. The median will increase or stay the same.

(ii) Including a value less than the mean will decrease the mean.

Always true.

(iii) Including any 4 values will not affect the median.

Sometimes true. True if 2 values are below and 2 above the median, but not if all 4 are on one side.

(iv) Including 4 values less than the median will increase the median.

Never true. The median will decrease or stay the same.

7The mean of 8, 13, 10, 4, 5, 20, y, 10 is 10.375. Find y.

Sum = 10.375 × 8 = 83. Known values add up to 70.

y = 83 − 70 = 13

8The mean of 15 values is 134. Find the sum.

Sum = 15 × 134 = 2010

9Data: 12, 47, 8, 73, 18, 35, 39, 8, 29, 25, p. Which numbers could be p if the median is 29?

Sorted without p: 8, 8, 12, 18, 25, 29, 35, 39, 47, 73. With p there are 11 values, so the median is the 6th value.

The 6th value is 29 only if p ≥ 29.

So p can be (iii) 40, (iv) 100, (v) 29, (vi) 47, (vii) 30

10Cycle rides in a week (dot plot).

Counts: 0 → 3, 1 → 1, 2 → 4, 3 → 7, 4 → 7, 5 → 5, 6 → 4, 7 → 6, 8 → 3, 10 → 2. Total = 42 students.

(i) Average = 193 ÷ 42 ≈ 4.6 times

(ii) Median = average of the 21st and 22nd values = 4 times

(iii) (a) Not valid — 3 students did not cycle at all. (b) Valid — most students cycled a few times. (c) Valid — those who cycled 8 or 10 times in 7 days must have cycled more than once on some days. (d) Not valid — at least 5 students did so; others (like those who cycled 7 times) may also have cycled twice on some day.

(e) Each value increases by 1, so the average becomes ≈ 5.6 and the median becomes 5

11Darts: describe the data using minimum, maximum, mean and median.

Total students = 62. Minimum = 1 trial, maximum = 10 trials.

Mean = (1 + 4 + 20 + 54 + 84 + 120 + 90 + 100) ÷ 62 = 473 ÷ 62 ≈ 7.6

Median = average of the 31st and 32nd values = 8

Advertisement

5.2 Visualising and Interpreting Data

12Space Jam: Which statements are valid inferences? Identify consecutive years where the worldwide count increased 2 times or more.

(a) Not valid — the count did not increase every year (for example, it fell in 2024).

(b) Valid — in 2022–24 the USA launched about 2000–2250 of 2500–2900 objects, about 34.

(c) Not valid — Nepal is not shown in the graph, so we cannot say.

(d) Valid — China (≈ 270) and Russia (≈ 100) together are about 400.

The count roughly doubled from 2016 to 2017 and from 2019 to 2020.

The data is probably collected from the objects that countries register with the United Nations each year.

Figure it Out (Page 122)

1Visualise the shop customers data on a line graph.
010203040MonTueWedThuFriSatSunVisitingPurchasing

Average customers visiting and purchasing

Both lines are highest on Sunday. The gap between visiting and purchasing is largest on Tuesday and Sunday.

2Average days of rainfall in each month.

(i) Rainy days are counted every month for many years, and the average for each month is found.

051015202530JFMAMJJASONDMangaluruNew DelhiPort BlairRameswaram

(ii) Average number of rainy days

(iii) New Delhi (from the graph): Jan 1, Feb 1.5, Mar 1.5, Apr 1, May 1.5, Jun 4, Jul 10, Aug 10, Sep 4, Oct 1, Nov 0.3, Dec 1.

(iv) Most rainy days: Port Blair (about 126 days). Least: New Delhi (about 36 days).

(v) New Delhi: July–August (June to September). Rameswaram: October–December.

3Births in India every month (line graph).

(i) The number of births goes up and down in the same way every year. It is highest around September–November (about 1.9–2 million) and lowest around April–June (about 1.5 million).

(ii) July 2017: about 1.7 million

(iii) About 3 years, from around April 2017 to April 2020.

(iv) The January values in 2018, 2019 and 2020 are nearly the same, about 1.7–1.8 million each.

(v) About 1.75 million per month × 12 ≈ 2.1 crore (21 million) births in 2019.

Values read from a graph are approximate.

13Infographic (Wheat vs Rice): answer the questions.

(i) Karnataka lies between Maharashtra (−15) and Andhra/Tamil Nadu (+85 to +92), near Goa (+57). Its value is likely about +60 to +70.

(ii) Rice most popular: Manipur (+100), Nagaland (+99), Mizoram (+97), Tripura (+96), Meghalaya (+95).

(iii) Wheat most popular: Rajasthan (−93), Haryana (−81), Punjab (−78), Madhya Pradesh (−60), Delhi (−45).

(iv) Nearly balanced: Bihar (+3), Maharashtra (−15), Uttarakhand (−18), Himachal Pradesh (−19).

14What can a strip say? Manoj’s activity strips.

(i) Light blue = sleeping, green = eating, orange = friends/hobbies/media/family, yellow = classes and studying, purple = showering/dressing/yoga, grey = travelling.

(ii) The strip with a long yellow block from 9:30 am to about 4:30 pm is a school day — Friday. The strip with classes only in the morning and a free afternoon is Saturday. The strip with no classes and long leisure time is Sunday.

(iii) On Sunday afternoon (about 2 pm to 5 pm): he travels at about 1:30 pm, has a long orange block and travels back at about 5 pm.

(iv) The school lunch break is at about 12:30 pm – 1:00 pm (the green box in the middle of the school day).

(v) He sleeps about 8–9 hours, wakes at about 7 am and sleeps by about 9 pm. He exercises every morning and takes a nap on weekends.

Figure it Out (Page 127)

1Mean Grids: (i) Fill the 3 × 3 grid with 9 distinct numbers so that the average along each row, column and diagonal is 10. (ii) Can it be done in another way?
8184
61014
16212

Each row, column and diagonal adds up to 30, so the average is 10.

(ii) Yes. Another grid: 9, 14, 7 / 8, 10, 12 / 13, 6, 11.

2Give two examples for each condition.

(i) Mean 8: 7, 8, 9 and 2, 10, 12.

(ii) Median 15.5: 10, 15, 16, 20 and 1, 14, 17, 30.

(iii) Mean 13.6 (sum 68): 10, 12, 14, 15, 17 and 4, 8, 16, 20, 20.

(iv) Mean = median: 1, 2, 3, 4, 5, 6 and 10, 10, 10, 10, 10, 10.

(v) Mean > median: 1, 2, 3, 4, 5, 15 (mean 5, median 3.5) and 2, 2, 2, 2, 2, 20.

3Fill in the blanks so that the median of 5, 21, 14, __, __, __ is 13. How many possibilities if only counting numbers are allowed?

With 6 values, the median is the average of the 3rd and 4th values, so they must add up to 26.

Example: 1, 12, 30 → sorted 1, 5, 12, 14, 21, 30. Median = (12 + 14) ÷ 2 = 13.

One blank can be any number 14 or more (like 30, 31, 32, …). So there are infinitely many possibilities.

4Fill in the blanks so that the mean of 3, 11, __, __, 15, 6 is 6.5. How many possibilities with counting numbers?

Sum must be 6.5 × 6 = 39. Known values add up to 35. So the two blanks add up to 4.

Possibilities: (1, 3), (2, 2), (3, 1) → 3 possibilities.

5Check whether each statement is true.

(i) The average of two even numbers is even.

Not always. (2 + 4) ÷ 2 = 3 is odd. (2a + 2b) ÷ 2 = a + b, which can be odd.

(ii) The average of any two multiples of 5 is a multiple of 5.

Not always. (5 + 10) ÷ 2 = 7.5.

(iii) The average of any 5 multiples of 5 is a multiple of 5.

Not always. (5a + 5b + 5c + 5d + 5e) ÷ 5 = a + b + c + d + e, which is a whole number but need not be a multiple of 5. Example: 5, 5, 5, 5, 10 has average 6.

6Two new students join Sudhakar’s class (average 150.2 cm).

(i) Only (c) is correct. We need the heights of the two new students. The others need not be measured again.

(ii) The new students add 149 + 152 = 301 cm, which is more than 2 × 150.2 = 300.4 cm. So (b) the average will increase (slightly, to about 150.22 cm).

(iii) (d) — we do not know the class median or the other heights, so we cannot say how the median changes.

7Is 17 the average of the data in the dot plot?

Counts: 14 → 2, 15 → 2, 16 → 3, 17 → 5, 18 → 4, 19 → 4, 20 → 3, 21 → 1, 23 → 1 (25 values).

Total distance of the values below 17 = 6 + 4 + 3 = 13. Total distance of the values above 17 = 4 + 8 + 9 + 4 + 6 = 31. They are not equal, so 17 is not the balancing point.

Mean = 443 ÷ 25 = 17.72. So No, 17 is not the average.

8Average weight 65.3 kg, median 67 kg. One person lost 2 kg and two gained 1 kg each. What happens to the mean and median?

Total change = −2 + 1 + 1 = 0. So the mean stays 65.3 kg.

The median may or may not change. It depends on where these people are in the order. We cannot say without the data.

9Retail price of iodised salt (2016–2025).

(i) Draw a line for each chosen state with years on the horizontal axis and price on the vertical axis.

(ii) Prices rose in most states, but not every year. Mizoram has the highest prices.

(iii) Gujarat’s price stayed almost the same (about ₹13–15) until a jump to ₹19.2 in 2025. Uttar Pradesh’s price rose steadily from ₹16 to about ₹27 and then dropped slightly.

(iv) West Bengal — from ₹9.47 to ₹23.99 (an increase of about ₹14.5, more than double).

(v) For example: Why are prices so different in different states?

10Primary source of energy for household lighting: which statements are valid?

(i) Valid — in 1983 about 84% of rural homes used kerosene, and about 64% of urban homes used electricity.

(ii) Valid — the kerosene line goes down in both graphs.

(iii) Not valid — in 2000 about 90% of urban homes used electricity (about 10% used kerosene).

(iv) Not valid — the graph shows the main lighting source, not power cuts.

11Time spent daily on hobbies and games.

(i) About 2 hours for urban children aged 10.

(ii) (c) 12 years

(iii) (a) Not correct — the time at 15 is less than at 10. (b) Not correct — an average does not tell us about every child.

14Sunrise and sunset times at 4 places.

The lower lines (around 05:00–08:00) are sunrise and the upper lines (around 16:00–20:00) are sunset.

(i) In January the sun rises earliest at Kibithu (about 5:50 am). Sunset is about 4:30 pm, so the day is about 10.5 to 11 hours long.

(ii) Srinagar has the longest day (in June, about 14.5 hours).

(iii) Kanyakumari’s day length hardly changes through the year, but places in the north have much longer summer days.

15Moonrise and moonset over a month.

(i) Purnima: when the moon rises around sunset (about 6 pm) — around the 15th. Amavasya: when the moon rises around sunrise (about 6 am) — around the 29th–30th.

(ii) The moon rises and sets about 50 minutes later each day.