9. Decimal Fractions
Solutions to Problem Sets 36 to 42 — writing, reading and converting decimals, and adding and subtracting decimal fractions. Maharashtra State Board (Balbharati), Grade Five Mathematics, Part Two.
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Key Ideas
Problem Set 36
- 3 910 = 3.9 — read as “three point nine”
- 1 410 = 1.4 — read as “one point four”
- 5 310 = 5.3 — read as “five point three”
- 810 = 0.8 — read as “zero point eight”
- 710 = 0.7 — read as “zero point seven”
Problem Set 37
- 9 110 = 9.1 — read as “nine point one”
- 9 1100 = 9.01 — read as “nine point zero one”
- 4 53100 = 4.53 — read as “four point five three”
- 78100 = 0.78 — read as “zero point seven eight”
- 5100 = 0.05 — read as “zero point zero five”
- 510 = 0.5 — read as “zero point five”
- 210 = 0.2 — read as “zero point two”
- 20100 = 0.20 — read as “zero point two zero”
Compare (1) and (2): 9 110 = 9.1 but 9 1100 = 9.01. With hundredths, an empty tenths place must be filled with 0. Also, 0.20 = 0.2, since 20 hundredths = 2 tenths.
Problem Set 38
(1) 6.13 — read as “six point one three”
- 6 — Units — 6
- 1 — Tenths — 1 × 110 = 0.1
- 3 — Hundredths — 3 × 1100 = 0.03
(2) 48.84 — read as “forty-eight point eight four”
- 4 — Tens — 40
- 8 — Units — 8
- 8 — Tenths — 8 × 110 = 0.8
- 4 — Hundredths — 4 × 1100 = 0.04
(3) 72.05 — read as “seventy-two point zero five”
- 7 — Tens — 70
- 2 — Units — 2
- 0 — Tenths — 0 × 110 = 0
- 5 — Hundredths — 5 × 1100 = 0.05
(4) 3.4 — read as “three point four”
- 3 — Units — 3
- 4 — Tenths — 4 × 110 = 0.4
(5) 0.59 — read as “zero point five nine”
- 0 — Units — 0
- 5 — Tenths — 5 × 110 = 0.5
- 9 — Hundredths — 9 × 1100 = 0.09
Problem Set 39
- ₹ 58.43 = 58 rupees 43 paise
- ₹ 9.30 = 9 rupees 30 paise
- ₹ 2.30 = 2 rupees 30 paise
- ₹ 2.3 = 2 rupees 30 paise (2.3 = 2.30)
₹ 2.3 is not 2 rupees 3 paise. 0.3 rupee = 3 tenths = 30 hundredths = 30 paise. 3 paise would be written ₹ 2.03.
- 6 rupees 25 paise = ₹ 6.25
- 15 rupees 70 paise = ₹ 15.70
- 8 rupees 5 paise = ₹ 8.05
- 22 rupees 4 paise = ₹ 22.04
- 720 paise = 700 paise + 20 paise = 7 rupees 20 paise = ₹ 7.20
- 58.75 m = 58 m 75 cm
- 9.30 m = 9 m 30 cm
- 0.30 m = 0 m 30 cm, that is, 30 cm
- 0.3 m = 0 m 30 cm, that is, 30 cm
- 1.62 m = 1 m 62 cm
- 91.4 m = 91 m 40 cm
- 7.02 m = 7 m 2 cm
- 0.09 m = 0 m 9 cm, that is, 9 cm
- 1 m 50 cm = 1.50 m (or 1.5 m)
- 50 m 40 cm = 50.40 m (or 50.4 m)
- 50 m 4 cm = 50.04 m
- 734 cm = 7 m 34 cm = 7.34 m
- 10 cm = 0.10 m (or 0.1 m)
- 2 cm = 0.02 m
- 6.9 cm = 6 cm 9 mm
- 20.4 cm = 20 cm 4 mm
- 0.8 cm = 0 cm 8 mm, that is, 8 mm
- 0.5 cm = 0 cm 5 mm, that is, 5 mm
1 cm = 10 mm, so the first decimal place of a length in centimetres gives the millimetres.
- 7 cm 1 mm = 7.1 cm
- 16 mm = 1 cm 6 mm = 1.6 cm
- 144 mm = 14 cm 4 mm = 14.4 cm
- 8 mm = 0.8 cm
Problem Set 40
- Two and a half = 2 12 = 2.5
- Two and a quarter = 2 14 = 2.25
- Two and three quarters = 2 34 = 2.75
- Ten and a half = 10 12 = 10.5
- Fourteen and three quarters = 14 34 = 14.75
- Sixteen and a quarter = 16 14 = 16.25
- Twenty-eight and a half = 28 12 = 28.5
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Problem Set 41
(1) ‘One and a half metre’ and ‘two and a half metres’
1.5 m + 2.5 m
Total = 4 m (4.0 m)
(2) ‘Four and three quarter rupees’ and ‘seven and a quarter rupees’
₹ 4.75 + ₹ 7.25
Total = ₹ 12 (₹ 12.00)
(3) ‘Six and a half metres’ and ‘three and three quarter metres’
6.5 m + 3.75 m = 6.50 m + 3.75 m
Total = 10.25 m
- 23.4 + 87.9 = 111.3
- 35.74 + 816.6 = 852.34
- 6.95 + 74.88 = 81.83
- 41.03 + 9.98 = 51.01
In (2), 816.6 is written as 816.60 so that both numbers have two decimal places.
- 51.4 cm + 68.5 cm = 119.9 cm
- 94.7 m + 1738.45 m = 1833.15 m
- ₹ 5158.75 + ₹ 841.25 = ₹ 6000.00
Problem Set 42
- 25.74 − 13.42 = 12.32
- 206.35 − 168.22 = 38.13
- 63.4 − 31.8 = 31.6
- 63.43 − 31.8 = 31.63
- 63.4 − 31.83 = 31.57
- 8.23 − 5.45 = 2.78
- 18.23 − 9.45 = 8.78
- 78.03 − 41.65 = 36.38
Compare (3), (4) and (5): always match the decimal places first. In (4), 31.8 becomes 31.80; in (5), 63.4 becomes 63.40.
Increase = 1.53 m − 1.48 m = 0.05 m. Since 1 m = 100 cm, 0.05 m = 5 cm.
Her height increased by 5 cm in a year.
Something More: Decimal Units of Measurement
| Quantity | Kilo (1000) | Hecto (100) | Deca (10) | Basic unit | Deci (1/10) | Centi (1/100) | Milli (1/1000) |
|---|---|---|---|---|---|---|---|
| Distance | kilometre | hectometre | decametre | metre | decimetre | centimetre | millimetre |
| Mass | kilogram = 1000 g | hectogram = 100 g | decagram = 10 g | gram | decigram | centigram | milligram |
| Volume | kilolitre = 1000 L | hectolitre = 100 L | decalitre = 10 L | litre | decilitre | centilitre | millilitre |
The textbook table gives only the distance row. The mass and volume rows follow the same pattern (in bold): each unit is 10 times the one on its right. The units used most often are kilometre, metre, centimetre, kilogram, gram, litre and millilitre.