Std 9 Science and Technology · Chapter 5

5. Acids, Bases and Salts

Complete solutions to the Exercises. Maharashtra State Board (Balbharati), Standard Nine Science and Technology.

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Exercises

1Identify the odd one out and justify.

(a) Chloride, nitrate, hydride, ammonium — odd one: Ammonium

Ammonium (NH4+) is a positively charged basic radical (cation). Chloride (Cl−), nitrate (NO3−) and hydride (H−) are negatively charged acidic radicals (anions).

(b) Hydrogen chloride, sodium hydroxide, calcium oxide, ammonia — odd one: Hydrogen chloride

Hydrogen chloride gives H+ ions in water, so it is an acid. Sodium hydroxide, calcium oxide and ammonia give OH− ions in water, so they are bases.

(c) Acetic acid, carbonic acid, hydrochloric acid, nitric acid — odd one: Carbonic acid

Carbonic acid (H2CO3) gives two H+ ions per molecule, so it is dibasic. Acetic acid (CH3COOH), hydrochloric acid (HCl) and nitric acid (HNO3) give one H+ ion each, so they are monobasic.

(d) Ammonium chloride, sodium chloride, potassium nitrate, sodium sulphate — odd one: Ammonium chloride

Ammonium chloride is formed from a strong acid (HCl) and a weak base (NH4OH), so it is an acidic salt (pH less than 7). The other three are formed from strong acids and strong bases, so they are neutral salts (pH 7).

(e) Sodium nitrate, sodium carbonate, sodium sulphate, sodium chloride — odd one: Sodium carbonate

Sodium carbonate is formed from a weak acid (carbonic acid) and a strong base (NaOH), so it is a basic salt (pH more than 7). The other three are neutral salts of strong acids and a strong base.

(f) Calcium oxide, magnesium oxide, zinc oxide, sodium oxide — odd one: Zinc oxide

Zinc oxide reacts with both acids and bases, so it is an amphoteric oxide. Calcium oxide, magnesium oxide and sodium oxide react only with acids, so they are basic oxides.

(g) Crystalline blue vitriol, crystalline common salt, crystalline ferrous sulphate, crystalline sodium carbonate — odd one: Crystalline common salt

Common salt (NaCl) crystals have no water of crystallisation. Blue vitriol (CuSO4·5H2O), ferrous sulphate (FeSO4·7H2O) and sodium carbonate (Na2CO3·10H2O) all contain water of crystallisation.

(h) Sodium chloride, potassium hydroxide, acetic acid, sodium acetate — odd one: Acetic acid

Acetic acid is a weak acid that dissociates only slightly in water, so it is a weak electrolyte. Sodium chloride and sodium acetate (salts) and potassium hydroxide (a strong base) dissociate almost completely, so they are strong electrolytes.

2Write down the changes that will be seen in each instance and explain the reason behind it.

(a) 50 ml water is added to 50 ml solution of copper sulphate.

Change: the blue colour of the solution becomes lighter. Reason: the quantity of copper sulphate stays the same but the volume of the solution doubles, so its concentration becomes half. The solution becomes more dilute, and the colour, which depends on the concentration of Cu2+ ions, fades.

(b) Two drops of the indicator phenolphthalein were added to 10 ml solution of sodium hydroxide.

Change: the colourless solution turns pink. Reason: phenolphthalein is colourless in acidic and neutral solutions but pink in basic solutions. Sodium hydroxide is a strong base, and its solution contains a large number of OH− ions.

(c) Two or three filings of copper were added to 10 ml dilute nitric acid and stirred.

Change: the copper filings slowly dissolve, the solution turns blue, and a colourless gas is given off which turns brown on coming in contact with air. Reason: copper reacts with nitric acid to form copper nitrate, Cu(NO3)2, whose solution is blue because of Cu2+ ions.

3Cu(s) + 8HNO3(aq) → 3Cu(NO3)2(aq) + 2NO(g) + 4H2O(l)

Copper is less reactive than hydrogen and does not displace hydrogen from dilute acids such as HCl or H2SO4. It reacts with nitric acid only because nitric acid is also an oxidising agent, so the gas given off is nitric oxide (NO), not hydrogen. The textbook’s table on page 66 shows Cu(NO3)2 + H2 as the products; the blue colour of copper nitrate is the change to note.

(d) A litmus paper was dropped into 2 ml dilute HCl. Then 2 ml concentrated NaOH was added to it and stirred.

Change: in dilute HCl the litmus paper turns red. After concentrated NaOH is added and stirred, it turns blue. Reason: HCl is an acid, and acids turn blue litmus red. The concentrated NaOH contains far more OH− ions than there are H+ ions in the dilute acid. It first neutralizes all the acid (H+ + OH− → H2O), and the excess base then makes the solution basic, which turns red litmus blue.

(e) Magnesium oxide was added to dilute HCl and magnesium oxide was added to dilute NaOH.

Change: magnesium oxide dissolves in dilute HCl, but there is no change in dilute NaOH. Reason: magnesium oxide is a basic oxide. It reacts with an acid to form a salt and water, but it does not react with a base.

MgO(s) + 2HCl(aq) → MgCl2(aq) + H2O(l)
MgO(s) + NaOH(aq) → no reaction

(f) Zinc oxide was added to dilute HCl and zinc oxide was added to dilute NaOH.

Change: zinc oxide dissolves in both. Reason: zinc oxide is an amphoteric oxide — it reacts with an acid as well as with a base, forming a salt and water in each case.

ZnO(s) + 2HCl(aq) → ZnCl2(aq) + H2O(l)
ZnO(s) + 2NaOH(aq) → Na2ZnO2(aq) + H2O(l)  (sodium zincate)

(g) Dilute HCl was added to limestone.

Change: brisk effervescence is seen and the limestone slowly dissolves. The gas turns limewater milky. Reason: limestone is calcium carbonate. Acids react with carbonates to give a salt, water and carbon dioxide gas; the bubbles are of CO2.

CaCO3(s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + H2O(l)

(h) Pieces of blue vitriol were heated in a test tube. On cooling, water was added to it.

Change: on heating, the blue crystals turn into a white powder and drops of water collect on the cooler upper part of the test tube. When water is added after cooling, the white powder turns blue again. Reason: blue vitriol contains five molecules of water of crystallisation. Heating drives this water out, the crystal structure breaks down, and the blue colour is lost. Adding water restores the hydrated form and its blue colour. These are physical changes.

CuSO4·5H2O (blue) —heat→ CuSO4 (white) + 5H2O

(i) Dilute H2SO4 was taken in an electrolytic cell and electric current was passed through it.

Change: bubbles of gas form at both electrodes. The volume of gas collected at the cathode is double that at the anode. Reason: dilute H2SO4 dissociates into ions, so the water conducts electricity and electrolysis of water takes place. Hydrogen gas is formed at the cathode and oxygen gas at the anode, in the volume ratio 2 : 1.

Cathode: 2H2O(l) + 2e− → H2(g) + 2OH−(aq)
Anode: 2H2O(l) → O2(g) + 4H+(aq) + 4e−
3Classify the following oxides into three types and name the types. (CaO, MgO, CO2, SO3, Na2O, ZnO, Al2O3, Fe2O3)
Basic oxidesCaO, MgO, Na2O, Fe2O3
Oxides of metals; react with acids to form a salt and water.
Acidic oxidesCO2, SO3
Oxides of non-metals; react with bases to form a salt and water.
Amphoteric oxidesZnO, Al2O3
React with acids as well as bases to form a salt and water.
4Explain by drawing a figure of the electronic configuration.

(a) Formation of sodium chloride from sodium and chlorine.

NaNa (2, 8, 1)+ClCl (2, 8, 7)1 electron transferredNa+Na⁺ (2, 8)Cl−Cl⁻ (2, 8, 8)Na⁺ Cl⁻ : one ionic bond (sodium chloride)

Sodium gives one electron to chlorine; both ions get a complete octet.

  • A sodium atom (2, 8, 1) has one electron in its outermost shell. It gives away this electron and becomes the sodium ion Na+ (2, 8), which has a complete octet.
  • A chlorine atom (2, 8, 7) has seven electrons in its outermost shell. It takes up the electron given by sodium and becomes the chloride ion Cl− (2, 8, 8), which also has a complete octet.
  • The oppositely charged Na+ and Cl− ions attract each other. This force of attraction is one ionic bond, and the stable ionic compound sodium chloride, NaCl, is formed.

(b) Formation of magnesium chloride from magnesium and chlorine.

ClCl (2, 8, 7)MgMg (2, 8, 2)ClCl (2, 8, 7)1 electron1 electronCl−Cl⁻ (2, 8, 8)Mg2+Mg²⁺ (2, 8)Cl−Cl⁻ (2, 8, 8)

Magnesium gives one electron to each of two chlorine atoms.

  • A magnesium atom (2, 8, 2) has two electrons in its outermost shell. It gives away both and becomes the magnesium ion Mg2+ (2, 8), with a complete octet.
  • Each chlorine atom (2, 8, 7) can take up only one electron. So two chlorine atoms are needed; each takes one electron and becomes a chloride ion Cl− (2, 8, 8).
  • The Mg2+ ion attracts the two Cl− ions, forming two ionic bonds. The ionic compound magnesium chloride, MgCl2, is formed.

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5Show the dissociation of the following compounds on dissolving in water, with the help of chemical equation and write whether the proportion of dissociation is small or large.
Hydrochloric acid: HCl(g) —water→ H+(aq) + Cl−(aq)  — large (strong acid)
Sodium chloride: NaCl(s) —water→ Na+(aq) + Cl−(aq)  — large (salt)
Potassium hydroxide: KOH(s) —water→ K+(aq) + OH−(aq)  — large (strong base)
Ammonia: NH3(g) + H2O(l) → NH4+(aq) + OH−(aq)  — small (weak base)
Acetic acid: CH3COOH(l) —water→ CH3COO−(aq) + H+(aq)  — small (weak acid)
Magnesium chloride: MgCl2(s) —water→ Mg2+(aq) + 2Cl−(aq)  — large (salt)
Copper sulphate: CuSO4(s) —water→ Cu2+(aq) + SO42−(aq)  — large (salt)

Strong acids, strong bases and salts dissociate almost completely in water, so the proportion of dissociation is large. Weak acids (acetic acid) and weak bases (ammonia) dissociate only partly; most of their molecules remain undissociated, so the proportion is small.

6Write down the concentration of each of the following solutions in g/L and mol/L.

Concentration (g/L) = mass of solute in g ÷ volume of solution in L; molarity (mol/L) = concentration in g/L ÷ molecular mass.

(a) 7.3 g HCl in 100 ml solution
Volume = 100 ml = 0.1 L; molecular mass of HCl = 1 + 35.5 = 36.5
g/L = 7.3 ÷ 0.1 = 73 g/L; mol/L = 73 ÷ 36.5 = 2 mol/L (2 M)
(b) 2 g NaOH in 50 ml solution
Volume = 50 ml = 0.05 L; molecular mass of NaOH = 23 + 16 + 1 = 40
g/L = 2 ÷ 0.05 = 40 g/L; mol/L = 40 ÷ 40 = 1 mol/L (1 M)
(c) 3 g CH3COOH in 100 ml solution
Volume = 0.1 L; molecular mass of CH3COOH = (12 × 2) + (1 × 4) + (16 × 2) = 60
g/L = 3 ÷ 0.1 = 30 g/L; mol/L = 30 ÷ 60 = 0.5 mol/L (0.5 M)
(d) 4.9 g H2SO4 in 200 ml solution
Volume = 200 ml = 0.2 L; molecular mass of H2SO4 = 2 + 32 + 64 = 98
g/L = 4.9 ÷ 0.2 = 24.5 g/L; mol/L = 24.5 ÷ 98 = 0.25 mol/L (0.25 M)
7Answer the following questions.

(a) Classify the acids according to their basicity and give one example of each type.

The basicity of an acid is the number of H+ ions obtained by the dissociation of one molecule of the acid. On this basis acids are of three types:

Monobasic acidsGive one H+ per molecule.
Example: HCl (also HNO3, CH3COOH)
Dibasic acidsGive two H+ per molecule.
Example: H2SO4 (also H2CO3)
Tribasic acidsGive three H+ per molecule.
Example: H3PO4 (also H3BO3)

(b) What is meant by neutralization? Give two examples from everyday life of the neutralization reaction.

The reaction in which an acid reacts with a base to form a salt and water is called neutralization. In it, the H+ ions of the acid combine with the OH− ions of the base to form water: H+ + OH− → H2O. For example, HCl + NaOH → NaCl + H2O.

  • Acidity in the stomach: when excess acid in the stomach causes discomfort, an antacid such as milk of magnesia (magnesium hydroxide), a base, is taken. It neutralizes the excess acid.
  • Acidic soil: when the soil in a field becomes too acidic, farmers add lime (calcium oxide) or slaked lime, which are basic. They neutralize the acid in the soil.
  • Other examples: toothpaste, which is basic, neutralizes the acid formed in the mouth that causes tooth decay; baking soda applied to an ant or bee sting neutralizes the acid injected.

(c) Explain what is meant by electrolysis of water. Write the electrode reactions and explain them.

Pure water is a bad conductor of electricity because it has very few ions. When a little salt, strong acid or strong base is dissolved in it and an electric current is passed, water decomposes into its constituent elements, hydrogen and oxygen. This decomposition of water by electric current is called electrolysis of water.

Cathode reaction: 2H2O(l) + 2e− → H2(g) + 2OH−(aq)
Anode reaction: 2H2O(l) → O2(g) + 4H+(aq) + 4e−
  • At the cathode (negative electrode): water molecules take up electrons coming from the cathode. Hydrogen gas is released, and OH− ions are formed, so the solution near the cathode becomes basic (turns red litmus blue).
  • At the anode (positive electrode): water molecules give up electrons to the anode. Oxygen gas is released, and H+ ions are formed, so the solution near the anode becomes acidic (turns blue litmus red).
  • For every 4 electrons, 2 molecules of hydrogen but only 1 molecule of oxygen are formed. So the volume of hydrogen collected at the cathode is double the volume of oxygen at the anode.
8Write the chemical equations for the following activities.
(a) NaOH solution was added to HCl solution:
NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)

(b) Zinc dust was added to dilute H2SO4:
Zn(s) + H2SO4(aq) → ZnSO4(aq) + H2(g)

(c) Dilute nitric acid was added to calcium oxide:
CaO(s) + 2HNO3(aq) → Ca(NO3)2(aq) + H2O(l)

(e) Carbon dioxide gas was passed through KOH solution:
CO2(g) + 2KOH(aq) → K2CO3(aq) + H2O(l)

(f) Dilute HCl was poured on baking soda:
NaHCO3(s) + HCl(aq) → NaCl(aq) + CO2(g) + H2O(l)

The textbook numbers this question (a), (b), (c), (e), (f) — there is no part (d). The same lettering is kept here.

9State the differences.

(a) Acids and bases

  1. Definition: an acid gives H+ as the only cation on dissolving in water, whereas a base gives OH− as the only anion.
  2. Taste and touch: acids are sour; bases are bitter and feel slippery or soapy.
  3. Litmus: acids turn blue litmus red; bases turn red litmus blue.
  4. Phenolphthalein: it stays colourless in acids but turns pink in bases.
  5. pH: an acidic solution has pH less than 7; a basic solution has pH more than 7.
  6. Examples: acids — HCl, H2SO4, CH3COOH; bases — NaOH, KOH, Ca(OH)2.

(b) Cation and anion

  1. Charge: a cation is a positively charged ion, whereas an anion is a negatively charged ion.
  2. Formation: a cation is formed when an atom gives away electrons; an anion is formed when an atom takes up electrons.
  3. Type of radical: cations are basic radicals; anions are acidic radicals.
  4. Usually formed from: cations mostly from metals (exception NH4+); anions mostly from non-metals (exception MnO4−).
  5. In electrolysis: cations move towards the cathode; anions move towards the anode.
  6. Examples: cations — Na+, Ca2+, Al3+; anions — Cl−, O2−, SO42−.

(c) Negative electrode and positive electrode

  1. Name: the negative electrode is called the cathode; the positive electrode is called the anode.
  2. Connection: the cathode is connected to the negative terminal of the battery; the anode is connected to the positive terminal.
  3. Ions attracted: the cathode attracts cations; the anode attracts anions.
  4. Electrons: at the cathode, electrons coming from the battery are taken up by the ions or molecules in the solution; at the anode, electrons are removed from the solution (or from the anode metal) and sent to the battery.
  5. Examples: in the electrolysis of copper sulphate, copper is deposited on the cathode while the copper anode dissolves. In the electrolysis of water, hydrogen is released at the cathode and oxygen at the anode.
10Classify aqueous solutions of the following substances according to their pH into three groups: 7, more than 7, less than 7. (Common salt, sodium acetate, hydrochloric acid, carbon dioxide, potassium bromide, calcium hydroxide, ammonium chloride, vinegar, sodium carbonate, ammonia, sulphur dioxide)
pH = 7 (neutral)Common salt, potassium bromide
pH more than 7 (basic)Sodium acetate, calcium hydroxide, sodium carbonate, ammonia
pH less than 7 (acidic)Hydrochloric acid, carbon dioxide, ammonium chloride, vinegar, sulphur dioxide
  • Common salt and potassium bromide are salts of a strong acid and a strong base, so they are neutral.
  • Sodium acetate and sodium carbonate are salts of a weak acid and a strong base (basic salts). Calcium hydroxide and ammonia are bases.
  • Ammonium chloride is a salt of a strong acid and a weak base (acidic salt). Carbon dioxide and sulphur dioxide are non-metal oxides that form acids in water. HCl and vinegar (acetic acid) are acids.
PProject

(1) Collect information about electroplating. Make a list of articles in day-to-day life, where this technique is used.

Electroplating is the use of electrolysis to deposit a thin layer of one metal on an article made of another metal. The article is made the cathode, a plate of the coating metal is the anode, and a solution of a salt of the coating metal is the electrolyte. It protects articles from rusting and corrosion and makes them look attractive.

Chromium platingBicycle handles and rims, taps and bathroom fittings, car bumpers and door handles
Nickel platingScissors, keys, locks, hand tools
Silver and gold platingImitation jewellery, spoons, trophies, medals, decorative items
Tin and zinc coatingFood cans (tin); iron buckets and roofing sheets (zinc)

(2) Obtain a sample of rainwater. Add to it a few drops of universal indicator. Measure its pH. Describe the nature of the sample of rainwater and write the effect it has on the living world.

Ordinary rainwater usually shows a pH of about 5.6 to 6.5, so it is slightly acidic. This is because carbon dioxide in the air dissolves in rainwater to form weak carbonic acid. Where the air contains oxides of sulphur and nitrogen from factories and vehicles, the rain becomes more strongly acidic (pH below 5.6); this is called acid rain.

Effects of acid rain: it makes soil acidic and less fertile; damages the leaves of plants and forests; makes lakes and rivers acidic, harming fish and other aquatic life; corrodes buildings, statues and monuments made of marble and limestone, and metal structures; and can irritate the skin and eyes of people and animals.

Your own reading may differ depending on where and when the sample is collected. Record the actual pH you measure.