2. Operations with Integers
Answers to all Figure it Out and in-text questions on multiplying and dividing integers and integer expressions. CBSE / NCERT Class 7 Ganita Prakash Part 2.
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2.1 A Quick Recap of Integers
| Sum | Difference | First number | Second number | |
|---|---|---|---|---|
| (a) | 27 | 9 | 18 | 9 |
| (b) | 4 | 12 | 8 | −4 |
| (c) | 0 | 10 | 5 | −5 |
| (d) | 0 | −10 | −5 | 5 |
| (e) | −7 | −1 | −4 | −3 |
| (f) | −7 | −13 | −10 | 3 |
Tip: first number = (sum + difference) ÷ 2, and second number = sum − first number.
1. The first movement is −4 and the final position is 5. What is the second movement?
−4 + b = 5, so b = 5 − (−4) = 9 (9 units to the right).
2. Movements 1, −2, 3, −4, …, −10. What is the final position?
(1 − 2) + (3 − 4) + … + (9 − 10) = 5 × (−1) = −5.
1. a is rightward (positive) and b is leftward (negative). b has the bigger magnitude, so P is to the left of 0.
2. a is rightward and b is leftward. a has the bigger magnitude, so P is to the right of 0.
3. a is leftward and b is rightward. They have equal magnitudes, so P = 0.
(a) To remove 18 positives from 7 positives, we add 11 zero pairs and remove 18 positives. 11 negatives are left. Adding 18 negatives to 7 positives also leaves 11 negatives. Both give −11.
(b) To remove 12 negatives from 4 positives, we add 12 zero pairs and remove the 12 negatives. 16 positives are left. Adding 12 positives to 4 positives also gives 16.
2.2 Multiplication of Integers
4 × (−6) = −24 and 9 × (−7) = −63.
In (−4) × 2, the multiplicand 2 is positive. A negative multiplier means removing it, so we remove 2 positive (green) tokens 4 times.
1. Using tokens, find:
(a) 3 × (−2) = −6
(b) (−5) × (−2) = 10
(c) (−4) × (−1) = 4
(d) (−7) × 3 = −21
2. 123 × 456 = 56088. Find:
(a) (−123) × 456 = −56088
(b) (−123) × (−456) = 56088
(c) 123 × (−456) = −56088
3. A simple rule to multiply two integers
Multiply the numbers without signs. If both have the same sign, the product is positive. If the signs are different, the product is negative.
Yes. Every set gives −8, because zero pairs add nothing. Each set is just −2.
Similarly, any token set for 4 (like 6 green and 2 red) taken 5 times gives 20.
Yes. Removing 2 positives is the same as adding 2 negatives. So, add 2 red tokens 4 times: −8.
(a) 4 × (−3) = −12 (b) (−6) × (−3) = 18 (c) (−5) × (−1) = 5
(d) (−8) × 4 = −32 (e) (−9) × 10 = −90 (f) 10 × (−17) = −170
−30 × 12 = −360 and 12 × −30 = −360.
14 × −5 = −70 and −5 × 14 = −70.
The product stays the same when we swap the numbers.
Maximum: all 50 correct → 50 × 5 = 250.
Minimum: all 50 wrong → 50 × (−2) = −100.
Distance moved = 45 × 3 = 135 m downwards. Position = 15 − 135 = −120. It is 120 m below the ground.
Every time, the product is −30,240.
Each number is a row number times a column number: rows 2, −7, 3, 5 and columns 4, −2, 6, −3 (for example, −28 = −7 × 4).
We always pick one number from each row and each column. So, the product is always (2 × −7 × 3 × 5) × (4 × −2 × 6 × −3) = −210 × 144 = −30,240.
The magic is in the way the numbers are made and arranged. To make a new grid, choose 4 row numbers and 4 column numbers and fill each box with their product.
Divide the numbers without signs. Same signs give a positive quotient. Different signs give a negative quotient.
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1. Find the values.
(a) 14 × (−15) = −210
(b) −16 × (−5) = 80
(c) 36 ÷ (−18) = −2
(d) (−46) ÷ (−23) = 2
2. Room temperature after 10 hours
32 + 10 × (−5) = 32 − 50 = −18°C.
3. Cement company (profit +8 per white bag, −5 per grey bag)
(a) 3000 × 8 + 5000 × (−5) = 24,000 − 25,000 = −1000. It is a loss of ₹1000.
(b) Loss on grey bags = 6400 × 5 = ₹32,000. White bags needed = 32,000 ÷ 8 = 4000 bags.
4. Fill in the blanks.
(a) (−3) × (−9) = 27
(b) 5 × (−7) = −35
(c) 7 × (−8) = −56
(d) (−11) × (−12) = 132
(e) (−56) ÷ (−8) = 7
(f) (−132) ÷ 12 = −11
5 × −3 × 4 in any order: (5 × −3) × 4 = −60, 5 × (−3 × 4) = −60, (5 × 4) × −3 = −60.
25 × −6 × 12: (25 × −6) × 12 = −1800, 25 × (−6 × 12) = −1800, (25 × 12) × −6 = −1800. The product is always −1800.
Sign rule: if the number of negative factors is even, the product is positive. If it is odd, the product is negative. (So, five −1s multiply to −1.)
Distributive property: (−2) × (4 + (−3)) = (−2) × 1 = −2, and (−2) × 4 + (−2) × (−3) = −8 + 6 = −2. They are equal.
2 + (−3) is 2 green and 3 red tokens. Its inverse is 2 red and 3 green tokens. Put this inverse in the bag 4 times.
We get 8 red and 12 green tokens, which is −8 + 12 = 4. This equals −4 × 2 + (−4) × (−3) = −8 + 12 = 4.
Machine 1 (a + b − c): (−10) + (−12) − (−9) = −13.
Machine 2: the rule is −(a × b) − c. Check: −(4 × 8) − (−3) = −32 + 3 = −29. Last row: −((−10) × (−12)) − (−9) = −120 + 9 = −111.
1. Find the values.
(a) (−5) × 15 = −75
(b) (−7) × 4 × (−1) = 28
(c) (−2) × (−1) × (−5) × (−3) = 30
2. Find the values.
(a) −3
(b) −21
(c) 28
3. Find the integer whose product with (−1) is:
(a) −27 (b) 31 (c) 1 (d) −1 (e) 0
4. 47 − 56 + 14 − 8 + 2 − 8 + 5 = −4. Find −47 + 56 − 14 + 8 − 2 + 8 − 5.
Every term has changed sign, so the new expression is (−1) × (−4) = 4.
5. Modified Collatz (even → half; odd → × (−3) + 1)
Starting with −7: −7, 22, 11, −32, −16, −8, −4, −2, −1, 4, 2, 1, −2, … (11 × (−3) + 1 = −32).
Starting with −21: −21, 64, 32, 16, 8, 4, 2, 1, −2, −1, 4, 2, 1, …
Starting with −6: −6, −3, 10, 5, −14, −7, 22, 11, −32, −16, −8, −4, −2, −1, 4, 2, 1, …
Pattern: every sequence reaches the loop 1, −2, −1, 4, 2, 1 and keeps repeating it.
6. Test with +4 for correct and −2 for incorrect
(a) 15 correct give 60 marks. 40 − 60 = −20 comes from wrong answers: 20 ÷ 2 = 10 incorrect. Questions in the test = 15 + 10 = 25.
(b) 5 correct give 20 marks. −10 − 20 = −30 comes from wrong answers: 15 incorrect. If the test has 25 questions, he left 5 unanswered.
7. Find the operations done by the machine.
The rule is a − b × c. Check: 4 − 8 × (−3) = 4 + 24 = 28. Last row: −16 − (−6) × (−9) = −16 − 54 = −70.
8. Temperature after 4 hours
8 + 4 × (−5) = 8 − 20 = −12°C
9. Three consecutive numbers with product (a) −6 (b) 120
(a) −3, −2, −1
(b) 4, 5, 6
10. Coins of +13 and −9 pibs
(a) +20 = 5 × 13 + 5 × (−9)
(b) +40 = 10 × 13 + 10 × (−9)
(c) −50 = 1 × 13 + 7 × (−9)
(d) +8 = 2 × 13 + 2 × (−9)
(e) +10 = 7 × 13 + 9 × (−9)
(f) −2 = 4 × 13 + 6 × (−9)
(g) +1 = 7 × 13 + 10 × (−9)
(h) Yes. 1568 = 122 × 13 + 2 × (−9) = 1586 − 18. (Since +1 can be made, any total can be made.)
11. Find the values.
(a) (−576) ÷ (−36) = 16
(b) 32 ÷ 648 = 481
(c) (−300) ÷ (−1215) = 2081
(d) (−1960) ÷ 280 = −7
12. Arrange in increasing order.
Values: (a) −1412, (b) 716, (c) 1412, (d) 3,70,272, (e) −3,70,272, (f) 3,35,472.
(e) < (a) < (b) < (c) < (f) < (d)
13. Given (−548) × 972 = −532656
(a) (−547) × 972 = −532656 + 972 = −531684
(b) (−548) × 971 = −532656 + 548 = −532108
(c) (−547) × 971 = −531684 + 547 = −531137
14. −207 × (33 − 7)
−207 × (33 − 7) = 207 × (−33 + 7) = −5382
15. Using 3, −2, 5, −6 and +, −, × once each
(a) Maximum: (−6) × ((−2) − (5 + 3)) = (−6) × (−10) = 60
(b) Minimum: ((3 + 5) − (−2)) × (−6) = 10 × (−6) = −60
16. Fill in the blanks in 5 ways.
(a) 0 + 6 × (−6); 4 + (−5) × 8; −6 + (−5) × 6; 4 + 10 × (−4); −36 + 1 × 0
(b) (5 − 2) × 4; (2 − 5) × (−4); (1 − 7) × (−2); (10 − 4) × 2; (−3 − (−9)) × 2
(c) 2 − (5 − 2); 0 − (4 − 3); 5 − (8 − 2); −3 − (0 − 2); 1 − (7 − 5)